You pull a 200 kg box straight up with a rope connected to a helicopter. If the magnitude of the tension is 2000 N, what is the acceleration of the box?
1.748 m/s^2
4.055 m/s^2
5.112 m/s^2
2.308 m/s^2

Acceleration of the box = 0.2 m / s²

Explanation:

Given:

Mass of box = 200 kg

Magnitude of the tension = 2,000 N

Find:

Acceleration of the box

Computation:

Ma = T - Mg

200(a) = 2,000 - (200)(9.8)

200(a) = 2,000 - 1960

200(a) = 40

a = 40 / 200

a = 0.2

Acceleration of the box = 0.2 m / s²

The acceleration  is 0.2 m/s^2.

Explanation:

Tension, T = 2000 N

mass, m = 200 kg

Let the acceleration is a.

So, by the use of Newton's second law

Net force = mass x acceleration

T - mg = ma

2000 - 200 x 9.8 = 200 x a

2000 - 1960 = 200 a

a = 0.2 m/s^2

what are the options.

explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day