You push an 8.0-kg box 2.0 meters on a frictionless surface with a force of 35 N, increasing its speed as you push. A) How much work do you do on the box?

B)How much work does normal force do on the box?

6 cos 34, 6 sin 34 trig

f is prop to m1xm2 double m1 double force

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j