A rock is thrown vertically downward from a building with an unknown initial (1-d) velocity. If the rock hits the ground after 3.50 s, with a final (1-d) velocity of -50.0 m/s, what is the change in height of the rock? [?] m

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

a is the best answer your welcome

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