If the length of the rod is 2.65 m, and the mass of the bob and the rod are both 1.4 kg, what is the period of this pendulum

  T = 5.66 s

Explanation:

The system formed by the bar plus ball forms a physical pendulum

        w =

the moment of inertia of a rod held at one end is

       I = m L²

we substitute

       w =

in this case the turning distance and the length of the rod are equal

        d = L

        w =

angular velocity and period are related

       w = 2π / T

        2π / T =

        T = 2π

let's calculate

       T = 2π

       T = 5.66 s

to be honest as much as i would love to answer this. i feel as if something's missing. just saying.