If an object of mass 70kg falls from a height of 500 m, what is the maximum velocity of the object?

H = 1/2 * g * t^2     since initial velocity is zero

v = g * t    where v is the final velocity

t = v / g

H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g

v = (2 * H * g)^1.2

v = (2 * 500 * 9.8)^1/2 = 99 m/s

Check: t = v / g = 99 / 9.8 = 10.1 sec

H = 1/2 * 9.8 * 10.1^2 = 500 m

the answer is to check all of them! they all apply well at least i think so!

an energy transformation flow diagram is shown

where is it ?