a ball of mass 0.2 kg is dropped from a height of 20m on impact to the ground it loses in 30 joule of energy calculate the height it reaches on rebound​

5 m

Explanation:

We'll begin by calculating the original potential energy. This can be obtained as follow:

Mass (m) = 0.2 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E₀) =?

E₀ = mgh

E₀ = 0.2 × 10 × 20

E₀ = 40 J

Next, we shall determine the new energy of the ball.

Energy (E₀) = 40 J

Energy lost (Eₗ) = 30 J

New energy (E) =?

E = E₀ – Eₗ

E = 40 – 30

E = 10 J

Finally, we shall determine height of the ball on rebound. This can be obtained as follow:

New energy (E) = 10 J

Mass (m) = 0.2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) =?

E = mgh

10 = 0.2 × 10 × h

10 = 2 × h

Divide both side by 2

h= 10 / 2

h = 5 m

Thus, the height of the ball on rebound is 5 m

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