A force of 19 Newton's is applied on a cart of 2 kilograms and it experiences a frictional force of 1.7 Newton’s what acceleration of the cart

ans: 8.65 m/s^2

Explanation:

since force is vector so for resultant

(F)resultant = [ (F1)^2 + |F1|•|F2|•cos180° + (F2)^2]^(1/2)

= (F1) - (F2)

= 19 - 1.7

= 17.3

SO,

force = ma

17.3 = 2×a

so, a= 8 65 m/s^2

true tan speed = ang vel x radius

e/c, where e is its total energy