Two small silver spheres, each of mass m=6.2 g, are separated by distance d=1.2 m. As a result of transfer of some fraction of electrons from one sphere to the other, there is an attractive force F=900 KN between the spheres. Calculate the fraction of electrons transferred from one of the spheres: To evaluate the total number of electrons in a silver sphere, you will need to invoke Avogadro's number, the molar mass of silver equal to 107.87 g/mol and the fact that silver has 47 electrons per atom.

4.60 × 10⁻⁸

Explanation:

From the given information;

Assuming that q charges are transferred, then:

where;

k = 9 ×10⁹

q = 0.012 C

No of the electrons transferred is:

Initial number of electrons =  N × 47 × no  of moles

here;

no of moles = 0.0575 mol

∴

Initial number of electrons =  

= 1.63 × 10²⁴

The fraction of electrons transferred  

= 4.60 × 10⁻⁸

all of the answers are correct.

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explanation:

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get