A large box of mass 4kg slides across a frictionless surface with a velocity of 12m/s to the right. It collides with a smaller box of mass 2kg that is stationary. The boxes stick together. What is the velocity of the two combined masses after the collision.

Explanation:

Let's call the large box "1" and the smaller box "2". The equation for this works so that momentum is conserved, as the Law states.

That says that the momentum of the larger box plus the momentum of the smaller box before the collision has to equal the momentum of the combined masses since they stick together. Filling in:

[(4(12) + 2(0)] = [(4 + 2)v] and

48 + 0 = 6v so

v = 8 m/s to the right

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.