A spring that obeys Hooke's law has a spring force constant of 266 N/m. This spring is then stretched by 28.4 cm. (a) What is the magnitude of the force required to stretch the spring by this distance

75.544 N.

Explanation:

From Hooke's law,

Applying,

F = ke Equation 1

Where F = Force required to stretch the spring, k = force constant of the spring, e = extension.

From the question,

Given: k = 266 N/m, e = 28.4 cm = 0.284 m

Substitute these values into equation 1

F = 266(0.284)

F = 75.544 N.

Hence the force required to stretch the spring is 75.544 N

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explanation:

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