a student pushes a load of mass 240kg for a distance of 2.3m. He exerts a constant horizontal force of magnitude 130N, as he does so. If the load starts from rest, what is its final velocity (neglecting frictional force) ​

Explanation:

Work applied

W = Fd = 130(2.3) = 399 J

Provided the surface is horizontal, the work applied will become kinetic energy

KE = ½mv²

v = √(2E/m) = √(2(299)/240) = √2.491666... ≈ 1.58 m/s

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