A 0.1 kg popper is placed on a table. When it pops up, it reaches a height of 2.0 meters. What was the
initial velocity of the popper off the table?

The initial velocity of the pooper off the table is approximately 9.264 m/s

Explanation:

The mass of the popper, m = 0.1 kg

The height the popper reaches, h = 2.0 meters

The initial velocity of the popper, 'u', is given by the following kinematic relation;

v² = u² - 2·g·h

Where;

h = The height the popper reaches = 2.0 m

v = The final velocity of the popper at the height it reached = 0 m/s

u = The initial velocity of the pooper off the table

g = The acceleration du to gravity, g ≈ 9.81 m/s²

Plugging in the values gives;

0² = u² - 2 × 9.81 × 2.0

∴ u - √(2 × 9.81 × 2.0) ≈ 9.264

The initial velocity of the pooper off the table, u ≈ 9.264 m/s.

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?

statement #3 on andre"s list is false.