When a force of 1600 Newtons is applied to a spring suspended from the ceiling, it stretches 2 meters. A mass of 50 kg is connected to the end of the spring and it comes to rest at its equilibrium position. The mass is then set into motion by being pushed up from its equilibrium position with a velocity of 28 m/s. (Let the positive direction be downwards.) 1. Write the equation of motion that governs the mass-spring system described above.
2. Identify the initial conditions and solve the differential equation from part (a) with the given initial conditions.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

area of focus

the answer to this is proletariats.

hope this : )