A round asteroid has a surface gravity of 0.0288 If the mass of the asteroid is 1.10x10^18 kg, what is its radius??

50473.45

Explanation:

(6.67×10^-11)(1.10×10^18)/(x)^2=0.0288.

im not to sure what it is

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever