A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's surface. Which of the following is closest the total kinetic energy gained by
the object as it falls?
A. 60. J
B. 590 J
C. 720 J
D. 1200 J

Given :

A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's

surface.

To Find :

The total kinetic energy gained by  the object as it falls.

Solution :

Since, only conservative force i.e gravity is applied on the object.

So, its total energy is constant.

Total kinetic energy gained = Total potential energy gained

K.E = mgh ( Here, g is acceleration due to gravity  = 9.8 m/s² )

K.E = 10 × 9.8 × 6 J

K.E = 588 J

Hence, this is the required solution.

trig 15.3 cos