Physics, 28.05.2021 09:50 cjjjjjjjjjjjjj
When we talk about energy from light that a surface receives, we use the word irradiance (E). Irradiance measures the
amount of energy per second (P) that arrives on a surface per unit area (A). As an equation, this idea can be expressed in
this way: E = P/A.
As the angle of the light source moves from 0° to 45°, the illuminated area (A) increases. You can see this increase in the
image. However, although the illuminated area increases, the energy per second (P) from the light is constant. What effect
will an increase in the angle of light, and therefore illuminated area (A), have on irradiance (E)?
Answers: 1
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Power can be defined as a. the distance over which work was done. b. how much work can be done in a given time. c. all the work in an given area. d. the energy required to do work.
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Unpolarized light of intensity i_0=750w/m^2 is incident upon two polarizers. after passing through both polarizers the intensity is i_2=280w/m^2. (a) what is the intensity of the light after it passes through the first polarizer in w/m^2? (b) write an equation for the angle between the polarizers in terms of the initial (i_0) and final (i_2) intensities. (c) find the angle between the polarizers in degrees.
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Need asap ‼️ 20 pts which gravitational force field diagram is drawn correctly? (answers in pictures below)
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When we talk about energy from light that a surface receives, we use the word irradiance (E). Irradi...
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