A 2.0 kg pellet is placed in the barrel of a toy gun and is propelled by a spring of force constant 50 N/m. The spring is compressed 2m and then released. Calculate the maximum velocity of the pellet when shot horizontally. *

10 m/s

Explanation:

Applying,

Kentic energy of the pelllet = Spring elestic energy

1/2(mv²) = 1/2ke²

mv² = ke² Equation 1

Where m = mass of the pellet, v = velocity of the pellet, k = force constant of the spring, e = extension of the spring

make v the subject of the equation

v = √(ke²/m) Equation 2

From the question,

Given: k = 50 N/m, e = 2 m, m = 2.0 kg

Substitute these values into equation 2

v = √(50×2²/2)

v = √(50×2)

v = √(100)

v = 10 m/s

the answer is b

explanation:

a, c, d, e are all applying about success strategies.