A 2.0 kg pellet is placed in the barrel of a toy gun and is propelled by a spring of force constant 50 N/m. The spring is compressed 2m and then released. Calculate the maximum velocity of the pellet when shot horizontally. *

10 m/s

Explanation:

Applying,

Kentic energy of the pelllet = Spring elestic energy

1/2(mv²) = 1/2ke²

mv² = ke² Equation 1

Where m = mass of the pellet, v = velocity of the pellet, k = force constant of the spring, e = extension of the spring

make v the subject of the equation

v = √(ke²/m) Equation 2

From the question,

Given: k = 50 N/m, e = 2 m, m = 2.0 kg

Substitute these values into equation 2

v = √(50×2²/2)

v = √(50×2)

v = √(100)

v = 10 m/s

the force required to move the cart is divided by three or 33.33 n.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this