So I was curious about parallel circuit. I first built four branches and only filled them with three light bulbs. Surprisingly, it looks something weird like the picture below (first one). When I filled the fourth branch with a light bulb, everything light equally and even brighter.

Okay, here's what I know. I know that the wire that is outside the branch (and connects with the fourth branch) has more current for sure because there is no resistance. However, why the first light bulb got brighter than the second one and so on? Secondly, why is the circuit with 4 light bulbs is brighter?

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

close lines strong magnet less close weaker

i believe the answer is a hope it and is correct