An B flat is played on a french horn, whose frequency is 466Hz. 1. what is the period of one vibration of this tone?
2. as the sound leaves the instrument at a speed of 343m/s, what is the wavelength?

Period of one vibration = 0.00215 second (Approx.)

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

Explanation:

Given:

Frequency of wave = 466 Hz

Find:

Period of one vibration

Wavelength {Is speed of sound is 343 m/s]

Computation:

Period of one vibration = 1/F

Period of one vibration = 1 / 466

Period of one vibration = 0.00215 second (Approx.)

Wavelength = Velocity / Frequency

Wavelength {Is speed of sound is 343 m/s] = 343 / 466

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

Explanation:

1. Period = 1/frequency = 1/466 = 0.002146s

2. Wavelength = Speed/frequency = 343/466 = 0.7361m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2