Physics, 19.05.2021 23:50 kellysimkin6196

A 2.5-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle with the rope at 10.0-m/s. a)What is the centripetal force that keeps the bucket moving in its circular path?b)What provides the centripetal force that keeps the bucket moving in its circular path?c)If the rope can hold 400-N of force, what is the maximum speed the bucket can move in its circular path? {Hint: Let the centripetal force be 400-N and solve for the speed.}

Answers: 1

Show answers

Another question on Physics

Physics, 21.06.2019 19:00

Many machines- including inclined planes such as ramps- increase the strength of the force put into the machine but decrease the distance over which the force is applied. true or false

Answers: 1

Answer

Physics, 22.06.2019 10:40

As you are trying to move a heavy box of mass m, you realize that it is too heavy for you to lift by yourself. there is no one around to , so you attach an ideal pulley to the box and a massless rope to the ceiling, which you wrap around the pulley. you pull up on the rope to lift the box. use g for the magnitude of the acceleration due to gravity and neglect friction forces. once you have pulled hard enough to start the box moving upward, what is the magnitude f of the upward force you must apply to the rope to start raising the box with constant velocity? express the magnitude of the force in terms of m, the mass of the box.

Answers: 1

Answer

Physics, 22.06.2019 11:00

Marcella is a four-year-old girl who is a victim of emotional child abuse. based on the child and family services improvement and innovation act of 2011, which action should the government take for marcella? a. the state should arrest marcella’s abuser. b. the state should find a home for marcella as soon as possible. c. the state should enforce stricter laws in the area where marcella resides. d. the state should provide medical assistance to marcella.

Answers: 3

Answer

Physics, 22.06.2019 13:30

The period of a pendulum varies directly as the square root of the length of the pendulum and inversely as the square root of the acceleration due to gravity. find the period when the length is 144 cm and the acceleration due to gravity is 980 cm per second squared, if the period is 7pi seconds when the length is 289 cm and the acceleration due to gravity is 980 cm per second squared.

Answers: 2

Answer

You know the right answer?

A 2.5-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle with the rope...

Questions