Information: A jet of steam at 100℃ is directed for a short time on to a large block of ice at 0℃. Some of the steam condenses to form water and some ice is melted. The condensed steam forms 0.40 kg of water at 0℃.

Questions:

1. Calculate the heat given out by this steam in changing to water without change in temperature. [Take the specific latent heat of vaporization of water as 2 200 kJ/kg].

2. Calculate the heat given out by this water as it cools to the temperature of the ice. [Take the specific heat capacity of water to be 4.2 kJ/(kg K).]

Isuck at math i am no sorry

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

What kind of enegia produces the mixture of bicarbonate and vinegar  chemical producetion