One long wire lies along an x axis and carries a current of 39 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 4.4 m, 0), and carries a current of 47 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 0.80 m, 0)

Explanation:

Magnetic field due to a long current carrying wire can be calculated as follows .

B = 10⁻⁷ x 2I / d where B is magnetic field , I is current .

The wire is along x -axis and the point is on y-axis at a distance of 0.8 m

Magnetic field at point of .8 m on y -axis

B₁ = 10⁻⁷ x 2 x 39 / 0.8  

= 97.5 x 10⁻⁷ T .

Second wire is parallel to  z-axis and passes through point on y-axis at a distance of 4.4 m . So the given point is at a distance of 4.4 - .8 = 3.6 m

Magnetic field

B₂ = 10⁻⁷ x 2 x 47 / 3.6  

= 26.11  x 10⁻⁷ T .

Both these magnetic fields are perpendicular to each other so

Resultant magnetic field

B = √ ( 26.11² + 97.5² ) x 10⁻⁷ T

= √( 681.73 + 9506.25 ) x 10⁻⁷ T

= √( 10187.98) x 10⁻⁷ T

= 100.93 x 10⁻⁷ T .

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..