A raindrop of radius R = 1.5 mm falling from a cloud at a height of h = 1200 meters above the ground. The drag coefficient C of the drop is 0.60. Assume that the descent is spherical throughout its fall. The density of water is Pw 1000 kg / m3, and the air density is Pa 1.2 kg / m3. If you know that a raindrop reaches its final velocity after falling a few meters. What is the final velocity?

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

It maybe because uranus is made of gas but uranus has a solid core in the middle

Dshould be the right answer i think