An object with a charge of 0.22C is separated by 0.67m from an object with a charge of -1.6. a) is the electric force between these two objects attractive or repulsive? explain

b) what is the magnitude of the electric force experienced by the object whose charge is 0.22C

c) what is the magnitude of the electric force experienced by the object whose charge is -1.6C?​

My answer is opptionc, just check with anyone else

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.