What is the total of a 10 ohm, 20 ohm, and 200 ohms resistors connected in a parallel

Answer is 6.452Ω

Explanation:

R1= 10Ω

R2= 20Ω

R3= 200Ω

1/R123= 1/R1+ 1/R2+ 1/R3

Find the LCM then find the inverse of the answer, then replace the values of the lettered resistors.

I hope this helps if not please let me know

i think the answer is a, hope this is right, that would be my best guess.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂