Acar moving east at 45 km/h turns and travels west at 30 km/h. what is the magnitude and direction of the change in velocity?

The magnitude and direction of the change in velocity is 75 m/s in west.

Explanation:

Given that,

Velocity of car = 45 km/h in east

Velocity of car = 30 km/h in west

We need to calculate the magnitude of the change in velocity

Using formula of change in velocity

Change in velocity = final velocity - initial velocity

Put the value into the formula

The direction of the the change in velocity is toward west.

Hence, The magnitude and direction of the change in velocity is 75 m/s in west.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

490 n

f=125n a=2.5m/s2