Find the magnitude of the horizontal force ,in n , required to push an object a distance of 2.00 meters if the force did 0.0430 j of work to perform the task .

                                       Work = (force) x (distance)

You have given the work and the distance,
so we can write:
                                  0.0430 J  =  (force) x (2 meters)

Divide each side by 2:    Force = (0.0430 J) / (2 meters) = 0.0215 Newton

                                       That's about 0.077 ounce of force.

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.