Tire pressure automobile tire pressure increases about 1 psi (pound per square inch) for each 108f increase in air temperature. at an air temperature of 558f, a tire’s pressure is 30 psi. write an equation that models the tire’s pressure as a function of air temperature.

Make the table first:

Tire’s

Pressure | Air Tempt

　30　|　   55 
　29　|　   45 
　28　|　   35 
　27　|　   25 
　26　|　   15 
　25　|　    5 
24.5　|　    0 

Solution:

P(24.5) = x(24.5 - 24.5) = 0 
P(25) = x(25 - 24.5) = 5 
　　　　　x(0.5) = 5 so x has to be 10 

To check:
P(26) = 10(26 - 24.5) = 15

P(T) = 10(T - 24.5) 

P(33) = 10(33 - 24.5) = 85

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s