The total aerodynamic force f acting on the airplane has a magnitude of 6250 lb. resolve this force into vertical and horizontal components

To solve this problem, we need the figure to help us understand. I believe I found the correct figure for this problem (see attached pic).

We see that the resultant force acts at an angle of 6 degrees from the vertical axis. The resultant force is also equivalent to the hypotenuse of the triangle. Now to solve this problem, we need the trigonometric functions specifically the cos and sin functions. We know that:

sin θ = side opposite to the angle / hypotenuse = Fx / F

cos θ = side adjacent to the angle / hypotenuse = Fy / F

Therefore calculating for Fx and Fy:

Fx = F sin θ

Fx = 6250 lb (sin 6)

Fx = 653.3 lb

Fy = F cos θ

Fy = 6250 lb (cos 6)

Fy = 6215.76 lb

i think it would be 5