Agrasshopper jumps straight up at 5.33 m/s. how much time does it take for it to return to earth? if u know .

1) Time to get the highest point of it pathway>

Vf = Vo - g*t

Vf = 0 (condition of maximum height)
Vo = 5.33 m/s
g = 9.81 m/s

=> t = Vo / g = 5.33 m/s / 9.81 m/s = 0.543 s

2) Time to return from the highest point = time to get to the highest point = 0.543 s

Total time = 0.543s + 0.543 s = 1.086 s ≈ 1.09 s

1.09 s