If the pendulum is brought on the moon where the gravitational acceleration is about g/6, approximately what will its period now be?

The pendulum movement is a famous situation manifesting the force of tension by the rope and the force of gravity coming into play. There are already derived equations explaining the behavior of the pendulum movement.

Period = t = 2π√(L/g)

Since, we don't have exact values for the parameters, let's just find the ratio to provide comparison. Let's find the ratio of the pendulum on the moon (t,moon) to the period of the pendulum on earth (t,earth).

t,moon/t,earth = 2π√(L/g/6) ÷ 2π√(L/g) = √6

Therefore, the period of the pendulum on the moon is the square root of 6 times that of in the earth.

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