Accelerating a car at 4.6 m/s. it takes 10 seconds to reach acceleratuon. starting velocity is 0 m/s. what is the final velocity?

I assume you mean the acceleration you want to reach is 4.6 m/s^2, and it takes 10 s linearly to get there.

Then this will be an integration problem, you need to integrate the velocity in form of acceleration with respect to time.

So a = 0.46t, where a is acceleration, t is time

So your velocity at time t equals to: a*t = 0.46t^2

So at t=10, V = 0.46 * 10^2 = 46 m/s

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way