Ablock of mass 10 kg slides down an inclined plane that has an angle of 30. if the inclined plane has no friction and the block starts at a height of 2 m, how much kinetic energy does the block have when it reaches the bottom? acceleration due to gravity is g = 9.8 m/s2.

E = 196 joules

Explanation:

It is given that,

Mass of the block, m = 10 kg

At the top, the block will have only potential energy which is given by :

At the bottom of the inclined plane, it will have only kinetic energy which is given by :

Applying the conservation of energy as :

E = 196 joules

So, the block will have 196 joules of kinetic energy when it reaches the bottom. Hence, this is the required solution.

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete