Abox is pushed down at an angle of 32 degrees on a rough surface. the box moves to the right. what equation should be used to find the net force in the y-direction?

Explanation:

We have four forces acting on the box. Taking the upward direction as positive direction for the vertical axis:

- The push, which pushes down along the ramp inclined at 32 degrees. Its vertical component will be , where F is the magnitude of the push

- The weight of the box, of magnitude , with m being the mass of the box and g being the acceleration of gravity (9.8 m/s^2). This force is already directed vertically downward, so we don't need to resolve it into the vertical direction

- The frictional force, of magnitude , where is the coefficient of friction, directed upward along the inclined plane. Its vertical projection will be

- The normal reaction, whose magnitude is equal to the component of the weight perpendicular to the inclined plane, but with opposite direction (upward): . If we resolve it along the vertical direction, we get

So, the net force along the y-direction will be

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)