Astone is dropped from the roof of a high building. a second stone is dropped 1.50 s later. how far apart are the stones when the second one has reached a speed of 13.0 m/s?

2nd stone time = 13.0/9.8 = 1.33 seconds

distance = 0.5*9.8*1.33^2 = 8.67 meters

1st stone time = 1.33+1.5 = 2.83 seconds

distance = 0.5*9.8*2.83^2 = 39.24 meters

39.24-8.67 = 30.57 meters apart

i. like it i'm gonna edit it tomorrow

the rearrangement of particles in a physical change. hope this