How many grams of li3n can be formed from 1.75 moles of li? assume an excess of nitrogen. 6 li(s) + n2(
g. → 2 li3n(s)

From the 1.75 moles of Li, the   formed is 20.317 grams.

The formation equation for will be:

For 6 moles of Li, there will be 2 moles of  .

For 1.75 moles of Li,   will be:

=

= 0.583 moles.

The molecular mass of   is 34.83 g/mol.

moles =

weight = moles molecular weight

weight of  formed = 0.583 34.83 grams

weight of   formed = 20.317 grams.

The  formed is 20.317 grams.

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