Calculate the amount of heat (kcal) released when 50.0g of steam at 100*c hits the skin, condenses, and cools to a body temperature of 37*c

conversion of steam at 100 C to water at 100 C :

m = mass of the steam = 50 g

L = latent heat of condensation of steam to water = 79.7 J/g

Heat released in conversion of steam to water is given as

Q₁ = mL

inserting the values

Q₁ = (50) (79.7)

Q₁ = 3985 cal

conversion of water at 100 C to water at 37 C :

ΔT = change in temperature = 100 - 37 = 63 C

c = specific heat of water = 1 cal/(gC)

m = mass of water = 50 g

Heat released in change of temperature is given as

Q₂ = m c ΔT

Q₂ = 50 x 1 x 63

Q₂ = 3150 cal

total heat released is given as

Q = Q₁ + Q₂

Q = 3985 + 3150

Q = 7135 cal

a, c, d, e are all applying about success strategies.

statement #3 on andre"s list is false.