Agirl is floating in a freshwater lake with her head just above the water. if she weighs 610 n, what is the volume of the submerged part of her body?

The volume of the submerged part of her body is

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

(I)

Where ''W'' is weight

⇒ If we consider ρ = (water density) and and replacing this values in the equation (I) ⇒

ρ.V.g = 610N

(II)

The force unit ''N'' (Newton) is defined as

Using this in the equation (II) :

We find that the volume of the submerged part of her body is

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards