If the number of troughs that pass a point in a given time increases, what has increased?

wavelength

frequency

amplitude

intensity

The frequency.

Explanation:

Each time that two consecutive troughs pass through a fixed point, means that the wave did a complete lapse, and this time-lapse is called the period of the wave.

Now, if we increase the number of troughs that pass in a fixed amount of time, this means that the period of the wave decreases (this means that the period is a little smaller)

Now, as we know, the frequency is inversely proportional (T = 1/f where T is the period and f is the frequency) to the period of the wave, so this would mean that the frequency is being increased

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

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