Acoin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates 3.0m,4.0m while a constant force acts on it. the force has magnitude 2.5 n and is directed at a counterclockwise angle of 100 from the positive direction of the x axis. how much work is done by the force on the coin during the displacement?

Answer

W=8.55Joule

Solution

In this question we have given

coin started sliding from origin (0,0) topoint (3m,4m)

therefore displacement of coin along x-axis,x=3m

displacement of coin along y-axis,y=4m

angle between applied force and positive x-axis=100

applied force=2.5N

Now we will find

component of force along x-axis, =

=

=-0.43

component of force in y direction, =

=

=2.46N  

work is done by the force on the coin during the displacement will be given as

W=

W =

=

W=8.55Joule

the total distance traveled by the car is

30km + 49km = 79 km .