What is the magnitude of the angular momentum relative to the origin of the 100 g particle in the figure(figure 1 ? express your answer to two significant figures and include the appropriate units?

Radius distance from origin to particle = √ (2²+1²) = √5 m = R 
I = MR² = (0.200)(5) = 1.00 kg-m² 
Θ = arctan 2/1 = 63.4° = R's angle CCW from horizontal 
V = 3.0 m/s 
V component that is at 90° to R = 3.0(sin 90°- 63.4°) = 3.0(sin 26.6°) = 1.3433 m/s 
w = [V component / R] = 1.3433/√5 = 0.601 rad/s 
size of angular momentum of particle relative to origin = Iw = (1.00)(0.601) = 0.601 kgm²/s

i hope I'm right

This is what a calorimeter is used for simpler ex, to measure calories in food.