1.5kg iron horse shoe initially at 600°c, it dropped into a bucket containing 20kg of water at 25°c. what is the final temperature. ( ignore heat capacity of the container )and assumed that a negligible amount of water boils always .(shc of water 4186jkg°c, shc of iron is 448jkg°c

Let final temperature be θ 
You have not given values for specific heat capacities, but any text-book will give the figures as 
Iron = 460 J/kgK 
Water = 4187 J/KgK 
Heat lost by horse shoe = heat gained by water (mC δt) 
1.5 x 460 x (600 - θ ) = 20 x 4187 x ( θ - 25) 
690 ( 600 - θ ) = 83740 ( θ - 25) 
414000 - 690 θ = 83740 θ - 2093500 
2507500 = 84430 θ 
θ = 29.7 C 
Final temperature of horse shoe and water is 29.7 C