An airplane touches down on the runway with a speed of 70 m/s2. determine the airplane after each second of its deceleration.

vf^2 = vi^2 + 2*a*d
---
vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters

The sun's gravitational pull is weaker on the planets that are closer to it, i think.

Hellothe asnwer is b.have a nice day