Physics, 03.12.2019 07:31 chinyere614

Time-outs are ineffective because
a. an adult uses a timer to make sure that the time-out is age appropriate.
b. the adult wins the power struggle.
c. the child quietly sits until the timer goes off.
d. a power struggle is created between the adult and the child.

Answers: 3

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Answer from: silverns

Time-outs are ineffective because

c. the child quietly sits until the timer goes off.

Explanation:

Time out was a technique proposed in the early 2000s with a poor notion of behavioralism control of the stimuli or conditions. However, after the children develop resistance to it by understanding that after a short while he or she will be delivered back to what he or she was doing there will be no permanent loss for them. Thus, it is a very ineffective technique created under the seeking of extension of the stimulus. An effective technique of removal of the variable would retrieve the stimuli and explain to the children it was retrieved from him or her because she didn't fulfill the expectations of behavior attached to it.

Answer from: Quest

co2reflects heat radiation back to earth buning coal and oil emits co2 globe warms

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Time-outs are ineffective because
a. an adult uses a timer to make sure that the time-out is...