A1.50-kilogram ball is attached to the end of a 0.520-meter string and swung in a circle. the velocity of the ball is 9.78 m/s. what is the tension in the string? 74.6 n 276 n 28.2 n 3.39 n

The tension in the string is 276 N.

Explanation:

It is given that,

Mass of the ball, m = 1.5 kg

Length of the meter stick, r = 0.52 m

Velocity of the ball, v = 9.78 m/s

The tension acting in the string is balanced by the centripetal force acting on it. Its formula is given by :

or

So, the tension in the string is 276 N. Hence, this is the required solution.

truck y has a greater velocity than truck x.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards