An eagle carries a fish up 50 m into the sky using 90 n of force. how much work did the eagle do on the fish? (work: w = fd)

4,500 J

Explanation:

Work is defined as the product between the force applied to move an object (F) and the distance through which the object has been moved through (d), times the cosine of the angle between the direction of the force and the displacement:

In this case, the work done by the eagle in lifting the fish is equal to the force applied by the eagle times the distance through which the fish has been moved, because the force is parallel to the displacement so :

In this problem, F=90 N and d=50 m. Therefore, the work done is

the answer would be 32*f

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day