If a lamp has a resistance of 136 ohms when it operates at a power of 1.00 × ^2, what is the potential difference across the lamp?

Given resistance in ohms and current in ampere, the power can be calculated by the equation,
                                      P = I² x R
where I is current, P is power, and R is resistance
Substituting the given values,
                            1.00 x 10² = (I²) x 136 ohms ;   I = 0.8575 amp
Then, by Ohm's law, the value of V = I x R. Substituting,
                                       V = (0.8575 amp) x (136 ohms) = 116.619 volts
Thus, the potential difference across the lamp is approximately equal to 116.619 volts. 

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