Abig league hitter attacks a fast ball. the ball has a mass of 0.16 kg. it is pitched at 38 m/s. after the player hits the ball, it is now traveling 44 m/s in the opposite direction. the impact lasted 0.002 seconds. how big of a force did the ballplayer put on that ball

6560 N

Explanation:

m = 0.16 kg

initial velocity = u = 38 m/s

final velocity = v = -44 m/s (opposite direction)

Momentum: product of mass and its velocity = p = m*v

change in momentum = initial momentum - final momentum  

                                       = m*v - m*u = 0.16*(-44)-0.16*38

                                       = 0.16(-44-38) = 0.16*(-82) = 13.12 kg.m/s

impact: large force per small time

force = change of momentum per unit time

         = 13.12/ 0.002 = 6560 kg.m/s^2 = 6560 N

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

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the ima (higher than 1m) will be greater than the ima with the height of 1m.