Abox weighing 46 newtons rests on an incline that makes an angle of 25° with the horizontal. what is the magnitude of the component of the box’s weight perpendicular to the incline?
(1)19 n
(2)21 n
(3)42 n
(4)46 n

The magnitude of the component of the box’s weight perpendicular to the incline can be olve using the formula:

F = wcos(a)

Where F is the box’s weight perpendicular to the incline

W is the weight of the box

A is the angle of the incline

F = (46)cos(25)

F = 42 N

The magnitude of the component of the box’s weight perpendicular to the incline is 42 N. Hence, option (3) is correct.

Explanation:

Given data:

Weight of box is, .

Angle of inclination is, .

In an inclined plane, the weight of box perpendicular to the incline is the cosine component of weight. Then,

Substituting the values as,

Thus, the magnitude of the component of the box’s weight perpendicular to the incline is 42 N.

For more details, refer to the link:

link

the answer would be c. motion and direction

i hope this : )