Calculate the energy of the orange light emitted, per photon, by a neon sign with a frequency of 4.89 × 1014 hz.

3.24 x 10⁻¹⁹ Joule

Further explanation

Given:

A neon sign with a frequency of 4.89 x 10¹⁴ Hz.

Question:

The energy of the orange light emitted per photon (in joules).

The Process:

The energy of a photon is given by

E = energy in joulesh = Planck's constant 6.63 x 10⁻³⁴ Jsf = frequency of light in Hz (sometimes the symbol f is written as v)

Let us find out the energy of the orange light emitted per photon.

Thus, we get a result of

- - - - - - - - - -

Notes:

When an electron moves between energy levels it must emit or absorb energy. The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons. A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.Learn moreWhat is the charge on 1.0 kg of protons?  link Determine the density of our sun at the end of its lifetime link   Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays link  

Keywords: calculate, the energy of the orange light emitted, per photon, by a neon sign, frequency, Planck's constant

Iread this book last year so take this with a grain of salt.gene jumps from the tree to compete with finny due to the fact that gene is always trying to do better than finny. he is put under the grasp of peer pressure due to finny almost forcing him to do this. ever since he first jumped finny kept pressuring him to jump since he thought gene enjoyed jumping.rather than uses this answer you should probably just reread chapters 3-4